125
115
105
95
85
75 2015107.05.04.03.0
2.0
TR, REFERENCE TEMPERATURE (
°
C)
VR, DC REVERSE VOLTAGE (VOLTS)
Figure 1. Maximum Reference Temperature
1N5817
40 30 23
60
80
RqJA (°C/W) = 110
125
115
105
95
85
75 2015107.05.0 304.03.0
40 30 23
RqJA (°C/W) = 110
80 60
Figure 2. Maximum Reference Temperature
1N5818
125
115
105
95
85
75 2015107.05.0 304.0 40
RqJA (°C/W) = 110
60
80
Figure 3. Maximum Reference Temperature
1N5819
40
30
23
TR, REFERENCE TEMPERATURE ( C)
°
VR, DC REVERSE VOLTAGE (VOLTS)
VR, DC REVERSE VOLTAGE (VOLTS)
TR, REFERENCE TEMPERATURE (
°
C)
1N5817, 1N5818, 1N5819
http://onsemi.com
3
NOTE 3. — DETERMINING MAXIMUM RATINGS
Reverse power dissipation and the possibility of thermal
runaway must be considered when operating this rectifier at
reverse voltages above 0.1 VRWM. Proper derating may be
accomplished by use of equation (1).
A(max)
where TA(max) =
TJ(max) =
PF(AV) =
PR(AV) =
Rq
=
TJ(max) − RqJAPF(AV) − RqJAPR(AV)
Maximum allowable ambient temperature
Maximum allowable junction temperature
Average forward power dissipation
(125°C or the temperature at which thermal
runaway occurs, whichever is lowest)
Average reverse power dissipation
Junction−to−ambient thermal resistance
Figures 1, 2, and 3 permit easier use of equation (1) by
taking reverse power dissipation and thermal runaway into
consideration. The figures solve for a reference temperature
as determined by equation (2).
R
J(max)
qJA
R(AV)
ubstituting equation (2) into equation (1) yields:
T
= T
− Rq
P
(
Inspection of equations (2) and (3) reveals that TR is the
ambient temperature at which thermal runaway occurs or
where TJ = 125°C, when forward power is zero. The
transition from one boundary condition to the other is
evident on the curves of Figures 1, 2, and 3 as a difference
in the rate of change of the slope in the vicinity of 115°C. The
data of Figures 1, 2, and 3 is based upon dc conditions. For
use in common rectifier circuits, Table 1 indicates suggested
factors for an equivalent dc voltage to use for conservative
design, that is: (4)
VR(equiv) = Vin(PK) x F
The factor F is derived by considering the properties of the
various rectifier circuits and the reverse characteristics of
Schottky diodes.
EXAMPLE: Find TA(max) for 1N5818 operated in a
12−volt dc supply using a bridge circuit with capacitive filter
such that IDC = 0.4 A (IF(AV) = 0.5 A), I(FM)/I(AV) = 10, Input
Voltage = 10 V(rms), RqJA = 80°C/W.
R(equiv)
. Read F = 0.65 from Table 1,
Step 1. Find ∴ VR(equiv) = (1.41)(10)(0.65) = 9.2 V.
Step 2. Find TR from Figure 2. Read TR = 109°C
Step 1. Find @ VR = 9.2 V and RqJA = 80°C/W.
Step 3. Find PF(AV) from Figure 4. **Read PF(AV) = 0.5 W
@I(FM)
I(AV) = 10 and IF(AV) = 0.5 A.
Step 4. Find TA(max) from equation (3).
Step 4. Find TA(max) = 109 − (80) (0.5) = 69°C.
*Values given are for the 1N5818. Power is slightly lower for the
N5817 because of its lower forward voltage, and higher for the
N5819.
Circuit
Load
Half W ave
Resistive Capacitive*
Full Wave, Bridge
Resistive Capacitive
Full Wave, Center Tapped*†
Resistive Capacitive
Sine W ave
Square Wave
0.5
0.75
1.3
1.5
0.5
0.75
0.65
0.75
1.0
1.5
1.3
1.5
**Note that VR(PK) ≈ 2.0 Vin(PK).†Use line to center tap voltage for Vin.
Table 1. Values for Factor F